4p^2+25p=-25

Solution for 4p^2+25p=-25 equation:

4p^2+25p=-25

We move all terms to the left:

4p^2+25p-(-25)=0

We add all the numbers together, and all the variables

4p^2+25p+25=0

a = 4; b = 25; c = +25;
Δ = b2-4ac
Δ = 252-4·4·25
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225}=15$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-15}{2*4}=\frac{-40}{8}
=-5
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+15}{2*4}=\frac{-10}{8}
=-1+1/4
$